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Cathodic Protection Calculator: Current and Anode Life

Protective current from the bare area and current density, and the life of magnesium, zinc or aluminum anodes.

Tool referenceDE-TOOL-8980

Method
Bare area × current density
Anodes
Magnesium, zinc and aluminum
Output
Current required and galvanic anode life

This cathodic protection calculator estimates how much current a buried or submerged steel structure needs and how long a set of galvanic anodes will last. The current is the bare steel area, which is the surface area times the coating breakdown, multiplied by a current density for bare steel in that soil or water. For one mile of 6 in. pipe with a good coating that leaves 2% of the surface bare, at 3 mA/ft², that is about 0.55 A, and fourteen 17 lb magnesium anodes last about 21 years at that current. Every value is a typical starting point that you can replace with test data.

Cathodic protection calculator: current and anode life

Estimate the protective current a coated or bare steel structure needs from its bare area and a published current density, then how long a set of galvanic anodes lasts at that current and how many you need for the design life. Every default is a typical value you can change. Pick a quick start or enter your own structure; the answer updates as you type.

The calculator needs JavaScript. The formulas and the typical values it uses are below.

Quick start Fills in the form. Change anything after.

The structure
Units

US units: inches, feet, square feet, mA/ft² and pounds. Metric: millimeters, meters, square meters, mA/m² and kilograms. Switching converts the values in the form.

Surface from

The outside diameter of the pipe, not its nominal size: 6 in. pipe is 6.625 in. (168.3 mm), 4 in. is 4.5 in., 2 in. is 2.375 in., 1 in. is 1.315 in.

Coating and environment

The current one square foot (or square meter) of bare steel needs. The published ranges are wide; a current requirement test on the structure gives a better value. Choosing an environment fills the high end of its range.

Published range for bare steel: 2 to 3 mA/ft². The field starts at the high end; use test data when you have it.

The share of the coated surface that is bare or exposed through damage at the end of the design life. 100 is bare steel. The form starts at 2%, which assumes a good modern coating such as FBE or extruded polyethylene; a well-applied one can stay well under 1% for years. For an older or damaged coating use 10% or more: the design examples in US Army TM 5-811-7 use coating efficiencies of 80 to 90%, that is 10 to 20% bare.

Galvanic anodes

The net weight of metal in one anode, without the backfill bag. Packaged magnesium anodes are commonly 3, 5, 9, 17, 32 and 48 lb (1.4 to 22 kg); zinc anodes 5 to 60 lb (2 to 27 kg).

Current for the life estimate

A galvanic anode puts out what the soil resistance and the driving voltage allow, which can be more or less than the requirement. If you have measured the anode current, use it for the life estimate.

More options

Magnesium at the usual 50% design efficiency. Theoretical 1,000 A·h/lb (2,200 A·h/kg).

The share of the anode that is consumed before it stops delivering useful current. 0.85 is common for packaged anodes; the right value depends on the anode's shape and core.

Result

Anodes last about 21 years, past the 20-year design life

9,158 ft² of surface with 2% bare is 183.2 ft² of bare steel. At 3 mA/ft², it needs about 0.549 A of protective current. 14 magnesium anodes of 17 lb each last about 21 years at that current. For 20 years, 14 anodes (226.5 lb in all) are needed.

Current required
0.549 A (549 mA)
Bare area
183.2 ft²
Estimated anode life
21 years
Anodes needed for 20 years
14

Galvanic anodes put out what the soil resistance and driving voltage allow, which can differ from the requirement. With a measured output, choose "Measured anode output" for the life estimate.

Estimated anode life against the design lifeBar: 14 anodes last about 21 years. Dashed line: the 20-year design life.Life of 14 anodes at this current21 yr025 yrdesign life 20 yr
Bar: estimated life of the anodes entered at the current used. Dashed line: the design life.

Screening estimate, not a guarantee of protection or of anode life. Protection is confirmed by measurements against the AMPP (NACE) SP0169 criteria. Cathodic protection design starts from soil and coating data, or ask an engineer.

Full results and steps
Surface area9,158 ft²
Bare area (2%)183.2 ft²
Current density for bare steel3 mA/ft²
Current required0.549 A
Current used for the life estimate0.549 A
Practical anode capacity500 A·h/lb
Consumption rate17.5 lb/A·yr
Anode mass entered238 lb
Estimated anode life21 years
Anode mass for 20 years226.5 lb, 14 anodes
  1. Surface: π × 6.625 in. ÷ 12 × 5,280 ft = 9,158 ft².
  2. Bare area: 9,158 ft² × 2% = 183.15 ft².
  3. Current: 183.15 ft² × 3 mA/ft² = 549.5 mA, or 0.5495 A.
  4. Life: 14 × 17 lb = 238 lb; 238 lb × 500 A·h/lb × 0.85 ÷ (0.5495 A × 8,760 h per year) = 21 years.
  5. For 20 years: 0.5495 A × 20 × 8,760 h ÷ (500 A·h/lb × 0.85) = 226.5 lb, so 14 anodes of 17 lb.

Designing, testing or replacing a CP system?

Dreiym designs, installs, tests and commissions galvanic and impressed current cathodic protection systems, PE-stamped where required. Our designs start from soil resistivity, coating condition and current requirement tests. Free quote; we typically respond within one business day.

Safety and limits

What this does not check: whether the anodes can deliver the current (anode-to-earth resistance from soil resistivity and anode size, for example by Dwight's equation, and the driving voltage between the anode and the protected steel), how the current spreads along the structure, interference with other structures, electrical isolation, and the protection criteria. Magnesium is not used in seawater for long lives, aluminum-zinc-indium anodes are for seawater and brackish water only, and zinc can passivate above about 49 °C (120 °F). The anode count with a measured output assumes the total output stays at that value; more anodes usually put out more current.

Screening tool: Screening estimate for education and planning. Not an engineering study or a design, and not a substitute for a licensed engineer's review where one is required.

How the calculation works
  • Surface area: π × outside diameter × length for a pipe, or the area entered.
  • Bare area = surface area × coating breakdown ÷ 100. Coating breakdown is 100% minus the coating efficiency.
  • Current required I = bare area × current density for bare steel. This is the method of the US Army design manual TM 5-811-7: area × current density × (1 − coating efficiency).
  • Anode life (years) = total anode mass × practical capacity × utilization factor ÷ (current × 8,760 h per year). Practical capacity already includes the current efficiency; the consumption rate is 8,760 ÷ capacity.
  • Anode mass for the design life = current × years × 8,760 ÷ (capacity × utilization factor); the number of anodes is that mass ÷ the mass per anode, rounded up.
  • One coating breakdown, the value at the end of the design life, is used for both the current and the anode mass. Offshore practice (DNV-RP-B401) uses a mean breakdown for the mass, so this is conservative for the mass.
Typical values used
Current density for bare steel (Air Force Manual AFM 88-9, as tabulated in US Army TM 5-811-7) and anode capacities. All are starting points to replace with test data.
ItemTypical value
Neutral soil0.4 to 1.5 mA/ft² (4 to 16 mA/m²)
Well-aerated neutral soil2 to 3 mA/ft² (22 to 32 mA/m²)
Wet soil1 to 6 mA/ft² (11 to 65 mA/m²)
Highly acidic soil3 to 15 mA/ft² (32 to 161 mA/m²)
Soil with sulfate-reducing bacteria6 to 42 mA/ft² (65 to 452 mA/m²)
Heated soil3 to 25 mA/ft² (32 to 269 mA/m²)
Stationary fresh water1 to 6 mA/ft² (11 to 65 mA/m²)
Moving fresh water with dissolved oxygen5 to 15 mA/ft² (54 to 161 mA/m²)
Seawater3 to 10 mA/ft² (32 to 108 mA/m²)
Magnesium, practical capacity500 A·h/lb (1,100 A·h/kg), 50% efficiency; consumption about 17.5 lb (8 kg) per ampere-year
Zinc, practical capacity335 A·h/lb (740 A·h/kg), 90% efficiency; consumption about 26 lb (11.8 kg) per ampere-year
Aluminum-zinc-indium, seawater2,000 A·h/kg (907 A·h/lb), DNV-RP-B401 design value
Utilization factor0.85, common for packaged anodes
Sources

Sources: US Army TM 5-811-7, Electrical Design, Cathodic Protection (1985; since replaced by Unified Facilities Criteria): current density table for bare steel from Air Force Manual AFM 88-9, and the current requirement method; UFC 3-570-06 and MIL-HDBK-1004/10: 50% current efficiency for magnesium anodes in design; theoretical capacities of magnesium (2,200 A·h/kg) and zinc (820 A·h/kg); DNV-RP-B401, Cathodic Protection Design (2021): design capacity of aluminum anodes in seawater; AMPP (NACE) SP0169, Control of External Corrosion on Underground or Submerged Metallic Piping Systems: protection criteria.

Cite or share this tool

Dreiym Engineering. Cathodic protection current and anode life calculator. Method: bare area × current density; anode mass × capacity × utilization ÷ current. https://www.dreiym.com/cathodic-protection-calculator/

Instructors and shops are welcome to link to this tool or put its address on a handout. It is free, needs no sign-up and works on a phone.

How to use the calculator

Enter the pipe’s outside diameter and length, or the surface area of a tank or other structure. Choose the soil or water: the current density field fills with the high end of the published range, and you can type your own value. Enter the coating breakdown, the share of the surface that is bare. Then choose the anode material, the net mass per anode, the number of anodes and the design life. If you have measured the anodes’ output, choose “Measured anode output” to estimate their life from it. The form works in US or metric units.

How to calculate cathodic protection current

  1. Find the surface area. For a pipe, π × outside diameter × length. For a tank, the bottom and the shell in contact with the soil or water.
  2. Find the bare area. Multiply by the coating breakdown: 2% bare is a coating efficiency of 98%. Use 10% or more for an older or damaged coating.
  3. Pick a current density for bare steel in that environment, from a current requirement test where possible.
  4. Multiply the bare area by the current density to get the current.
  5. Check the anodes. Anode life in years = anode mass × practical capacity × utilization factor ÷ (current × 8,760 hours).

Worked example

One mile (5,280 ft) of 6 in. steel pipe, 6.625 in. outside diameter, with a good coating that is 2% bare, in well-aerated neutral soil:

  • Surface: π × 6.625 ÷ 12 × 5,280 = 9,157.7 ft².
  • Bare area: 9,157.7 × 0.02 = 183.15 ft².
  • Current at 3 mA/ft²: 183.15 × 3 = 549.5 mA, or 0.5495 A.
  • Anodes: magnesium at 500 A·h/lb (50% efficiency) with a utilization factor of 0.85. For 20 years: 0.5495 × 20 × 8,760 ÷ (500 × 0.85) = 226.5 lb, so fourteen 17 lb anodes (238 lb). Their life at 0.5495 A is 238 × 500 × 0.85 ÷ (0.5495 × 8,760) = 21.0 years.

Pick the “Coated pipeline, 1 mile” quick start in the calculator above to see each step.

Typical values and where they come from

  • Current density for bare steel: 0.4 to 1.5 mA/ft² in neutral soil, 2 to 3 in well-aerated neutral soil, 1 to 6 in wet soil, 3 to 15 in highly acidic soil, 6 to 42 in soil with sulfate-reducing bacteria, 3 to 25 in heated soil, 1 to 6 in stationary fresh water, 5 to 15 in moving fresh water with dissolved oxygen and 3 to 10 in seawater (Air Force Manual AFM 88-9, as tabulated in US Army TM 5-811-7). Choosing an environment in the calculator fills the high end of its range.
  • Coating breakdown: no single value fits every coating. The calculator starts at 2% bare, which assumes a good modern coating such as FBE or extruded polyethylene; a well-applied one can stay well under 1% bare for years. Older or damaged coatings can reach 10% or more, and the design examples in TM 5-811-7 use coating efficiencies of 80 to 90%, that is 10 to 20% bare.
  • Magnesium anodes: 1,000 A·h/lb (2,200 A·h/kg) in theory and about 50% efficient in service, so about 500 A·h/lb (1,100 A·h/kg), or 17.5 lb (8 kg) per ampere-year.
  • Zinc anodes: 372 A·h/lb in theory and about 90% efficient, so about 335 A·h/lb, or 26 lb per ampere-year.
  • Aluminum-zinc-indium anodes, seawater and brackish water only: 2,000 A·h/kg, the seawater design value of DNV-RP-B401. The calculator does not accept them in soil.
  • Utilization factor: 0.85 is common for packaged anodes; the right value depends on the anode’s shape and core.

What the calculator does not check

It does not check whether the anodes can deliver the current. A galvanic anode’s output depends on the soil resistivity, the anode’s size and the driving voltage between the anode and the protected steel. It also does not show how the current spreads along a long pipe, interference with other structures, or whether the structure meets the protection criteria of AMPP (NACE) SP0169, which only measurements can confirm. It uses one coating breakdown, the value at the end of the design life, for both the current and the anode mass, which is conservative for the mass. With a measured output, the anode count assumes the total output stays at that value; more anodes usually put out more current.

Frequently asked questions

How many magnesium anodes do I need?

Divide the anode mass needed for the design life by the mass of one anode. The mass is current × years × 8,760 ÷ (capacity × utilization factor). At 0.5 A for 20 years with magnesium, that is about 206 lb, or thirteen 17 lb anodes. Then check that the anodes can deliver that current in your soil.

Magnesium or zinc?

Magnesium has an open-circuit potential of about −1.55 to −1.75 V to a copper-copper sulfate electrode, a driving voltage of about 0.7 to 0.9 V against steel protected at −0.85 V, so it suits soils of higher resistivity. Zinc, at about −1.1 V, has about 0.25 V of drive; it is used in low-resistivity soil and in seawater, where its high current efficiency pays off. Above about 49 °C (120 °F) zinc can passivate.

What current density should I use?

Best is a current requirement test on the structure itself: apply a temporary current and measure the potential shift. Without one, use the published range for the environment, and the high end for a design that has to work in the wettest or most corrosive season.

Is 20 years a typical design life?

We design galvanic systems for 20 years and impressed current systems for 30 years unless the owner specifies otherwise.

When to bring in an engineer

A cathodic protection design starts from soil resistivity, coating condition and a current requirement test, and is confirmed by a commissioning survey. Dreiym designs, installs, tests and commissions galvanic and impressed current systems, PE-stamped where required. Our corrosion team includes Stepan V. Eero, P.E., an AMPP (formerly NACE) CP4 Cathodic Protection Specialist. Related tool: the galvanic corrosion chart. See our cathodic protection design, soil corrosivity analysis and CP potential survey services, or contact us for a free quote. We typically respond within one business day.

Need more than a screening estimate?

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